Applying parametric subs. for diff. (Hinglish) | Cont. and diff. | Grade 12 | Math | Khan Academy

From the creator

In this video, we learn how to apply parametric substitutions for differentiation. We look at clues that the function provides for identifying substitutions. We then verify if the substitutions work by plugging them back in the function. We then differentiate both x and y with respect to the parameter. We then find dy/dx and eliminate the parameter from the solution. Courses on Khan Academy are always 100% free. Start practicing—and saving your progress—now! (https://www.khanacademy.org/math/ncert-class-12/x7ce8ca9c5869750b:continuity-and-differentiability-ncert-new/x7ce8ca9c5869750b:derivatives-of-functions-in-parametric-forms/e/differentiate-parametric-functions) Timestamps: 00:00 Breaking down the problem 00:45 Strategy for identifying substitutions 02:09 Verifying the substitutions 03:37 Differentiating with respect to the parameter 04:23 Finding differentiation of y with respect to x 04:52 Eliminating the parameter from the solution Khan Academy India is a nonprofit organization with the mission of providing a free, world-class education for anyone, anywhere. We have videos and exercises that have been translated into multiple Indian languages, and 15 million people around the globe learn on Khan Academy every month. Support Us: https://india.khanacademy.org/donate Created by Ashish Gupta

Published 2025-03-11 · Watch on YouTube ↗
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